the hypotenuse is 17...you messed up your question....the legs are 8 and 15....and the hypotenuse is 17....
take leg A = 8 and leg B = 15
the hypotenuse C^2 = A^2 + B^2
C^2 = 8^2 + 15^2
C^2 = 289
C = 17
if you have the question as is...there'd be no answer
2007-06-16 15:18:15
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answer #1
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answered by Yogaflame 6
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By Pythagoras Rule:
Hypotenuse^2 = Leg1^2 + Leg2^2
15 x 15 = 8 x 8 + Leg2^2
Leg2^2 = 225 - 64
Leg2^2 = 161 = 12.6885
2007-06-16 15:22:41
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answer #2
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answered by Hell's Angel 3
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By Pythagoras x^2 + 8^2 = 15^2
So x^2 = 225-64 = 161.
So x is sqrt(161), which is none of the answers above.
Re your other question, you need to explain what Y is before anyone can help you with the volume.
2007-06-16 15:19:14
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answer #3
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answered by tsr21 6
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Let other leg be x
15² = 8² + x²
x² = 15² - 8²
x² = (15 - 8).(15 + 8)
x² = 7 x 23
x² = 161
x = 12.7
None of above answers apply?
2007-06-17 04:26:52
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answer #4
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answered by Como 7
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Pythagorean theorem
a^2 + b^2 = c^2
15^2 + 8^2 = c^2
c^2 = 289
c = 17
2007-06-16 15:20:13
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answer #5
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answered by 7
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the answer is the square root of 161 (225-64) so it's none of your answers provided
2007-06-16 15:40:11
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answer #6
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answered by Hakim 3
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okay .use phytogras's therum A Squared + b Squared=C Squared
| hypotenuse (c)
a |
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|_________________
b
X Squared +(8) Squared=15 squared
or you can use the sin,cos and tan if you know he angles in the triangle
2007-06-16 15:22:03
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answer #7
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answered by Anonymous
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process of elimination. the hypotenuse MUST be the LONGEST side. so the leg can't be B or C or D.
All that is left is A.
2007-06-16 15:19:55
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answer #8
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answered by Anonymous
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