2007-06-16 08:53:44 · 8 answers · asked by The Girl 2 in Science & Mathematics ➔ Mathematics
exponent rule
a^m * a^b = a^(m + n)
4^1 * 4^3 * 4^8
= 4^(1 + 3 + 8)
= 4^(12)
2007-06-16 08:58:15 · answer #1 · answered by 7 · 0⤊ 0⤋
a^n * a^m = a^ ( n + m )
4*4^3*4^8 = 4 ^ ( 1+3+8 ) = 4 ^ 12
2007-06-16 09:01:27 · answer #2 · answered by pioneers 5 · 0⤊ 0⤋
4^12
2007-06-16 09:00:38 · answer #3 · answered by GTB 7 · 0⤊ 0⤋
4 * 4^3 * 4^8 = 4^1 * 4^3 * 4^8 = 4^(1 + 3 + 8) = 4^12.
In general, a^m * a^n = a^(m+n).
2007-06-16 08:59:45 · answer #4 · answered by jcastro 6 · 0⤊ 0⤋
4^12
(4^1)*(4^3)*(4^8)
1+3+8=12
2007-06-16 08:56:49 · answer #5 · answered by ritic87 2 · 0⤊ 0⤋
Order of Operations
I believe it would work out to 4*64*65536
Or, as was said, 4^12
2007-06-16 08:57:30 · answer #6 · answered by waruv 2 · 0⤊ 1⤋
add the exponents only.
4 = 4^1
4^12 is correct.
2007-06-16 08:57:48 · answer #7 · answered by Rainman 5 · 0⤊ 0⤋
4^12
The reason the teacher give 64^12 is that it be correct, if, you do it wrong.
2007-06-16 09:05:21 · answer #8 · answered by Snaglefritz 7 · 0⤊ 0⤋