21 and 15
21+15=36
21-15=6
how i got my answer
x + y = 36
x - y = 6
x = 6 + y = 36 - y
2y = 30
y = 15
x = 6 + 15 = 21
2007-06-16 08:03:15
·
answer #1
·
answered by jellybeanqueen 3
·
0⤊
1⤋
There are 2 equations given. First sentence: x^2 + y^2 = 20 2nd sentence: x - y = -6 this is definitely a structures of equations; those equations might desire to be solved via substituting between the variables in terms of the different. x = y - 6 (y - 6)^2 + y^2 = 20 y^2 - 12y + 36 + y^2 = 20 2y^2 - 12y + 36 = 20 y^2 - 6y + 18 = 10 y^2 -6y + 8 = 0 (y - 4)(y - 2) = 0 y = 4,2 as a results of fact there are 2 ideas for y, the two solutions might desire to be checked to be sure whether the ideas fulfill the situations from first and 2nd sentence. For y = 4, x = y - 6 x = 4 - 6 x = -2 First sentence: x^2 + y^2 = 20 (-2)^2 + 4^2 = 20 4 + sixteen = 20 20 = 20 2nd sentence: x - y = -6 -2 - 4 = -6 -6 = -6 y = 4 and x = -2 fulfill the situations. verify whether y = 2 might fulfill the comparable situations. For y = 2, x = y - 6 x = 2 - 6 x = -4 First sentence: x^2 + y^2 = 20 (-4)^2 + 2^2 = 20 sixteen + 4 = 20 20 = 20 2nd sentence: x - y = -6 -4 - 2 = -6 -6 = -6 y = 2 and x = -4 additionally fulfill the situations. this suggests the 1st variety must be -2, however the 2nd variety might desire to be 4, or the 1st variety must be -4, however the 2nd variety might desire to be 2. wish this helps.
2016-10-09 08:22:39
·
answer #2
·
answered by ? 4
·
0⤊
0⤋
I have NO idea what all this x & y stuff relates to, I worked the problem like this & got the same answers...I took 36 & subtracted the 6 to get 30, then I cut that number in half, getting 15. I then just added 6 to that 15 to get the sum of 21. To check it, I just added up the 15 to the 21 to get the original sum of 36. This tells me that I was correct because it all comes back to where it started. I failed in mathematics as a child, yet it seems that I have the ability to do these eqations in my head if I need to! I'll never understand why any of this is important to having a happy life! That was fun...thanks!
2007-06-16 08:17:31
·
answer #3
·
answered by Anonymous
·
0⤊
0⤋
21+15=36 21-15=6
2007-06-16 08:17:38
·
answer #4
·
answered by Rahshon B 1
·
0⤊
0⤋
15 and 21
2007-06-16 08:05:02
·
answer #5
·
answered by reems 1
·
1⤊
0⤋
ok look, no confusing math with a keyboard. and no algebra
18 goes into 36 twice. 6 divided by 2 is 3. add 3 to 18 and subtract 3 from 18.
15 and 21, that simple
2007-06-16 08:07:52
·
answer #6
·
answered by toshiomagic 3
·
0⤊
0⤋
x + y = 36
x - y = 6
x = 6 + y = 36 - y
2y = 30
y = 15
x = 6 + 15 = 21
2007-06-16 08:02:03
·
answer #7
·
answered by Anonymous
·
0⤊
1⤋
this is simultaneous equation problem....
x+y=36
x-y=6
-2y=-30
y=15
you now plug in the value for y to find what x is to any of the problems coz you'll find the same answer anyway...so, x-(15)=6
x=21
and it is true that;
21+15=36
21-15=6
2007-06-16 08:18:42
·
answer #8
·
answered by petite fille 2
·
0⤊
0⤋
x - y = 6 and x + y = 36
solving simultaneously
2x = 42
x = 21
substituting x
21 - y = 6
y = 21 - 6 = 15
y = 15
2007-06-16 08:04:17
·
answer #9
·
answered by rohan v 2
·
0⤊
1⤋
X + Y = 36
X - Y = 6
=>
2*X = 42
=>
X=21
=>
Y=15
have fun ;)
2007-06-16 08:02:18
·
answer #10
·
answered by Farshad Gh 2
·
0⤊
1⤋