Find the length of the ladder to the nearest thousandth.?

Question

The base of a ladder is 4 feet away from the wall. The top of the ladder is 8 feet from the floor. Find the length of the ladder to the nearest thousandth.

Can someone help me with this problem

Answer 1

first draw a picture
then you will see that you need to use pythagorean theorem

4^2 + 8^2 = L^2
16 + 64 = L^2
80 = L^2
L = sqrt(80)
L = 8.944

Answer 2

The ladder forms a right angle triangle along with the fllor and the wall.
Let the length of the ladder be x ft
then x^2=4^2+8^2
or,x^2=16+64=80
x=8.944
therefore the length of the ladder is
8.944 ft

Answer 3

Just use the Pythagrean Theorem (c^2 = a^2 + b^2)
Let L = length of ladder
Then l^2 = 4^2 + 8^2 = 80
L = sqrt(80) = 4sqrt(5)
L = approximately = 8.944 feet

Answer 4

Just use the Pythagorean Theorem:
a^2 + b^2 = c^2

a and b are the legs of the trianble (or your height and base) and c is the hypotenuse (your ladder)

So:
4^2 + 8^2 = c^2
c^2 = 80
c= 8.944 feet

Answer 5

okay, since we know the wall and the ground form a 90 degree angle, we know thatthe 4 foot segment and the 8 foot segment form a 90 degree angle so it must be a right triangle, so we can use the pythagoream therom.

a squared+b squared= c squared
a=4
b=8
c=the last side of the triangle

4 squared+8 squared=c squared

16+64=c squared

16+64=80
80=c squared
c=8.944 feet