can u give me info on rotational motion, angular velocity, rotational kinatic energy, moment of inertia...?

Question

torque, angular velocity rotational kinetic energy and linear kinetic energy?...plz..I have this physics report i have to write about those listed above in relation to this wheel i designed. if you know any info about those things about can yooh please tell me. it would be much appreciated. even if you just tell me what they are in relation to a wheel.

Answer 1

Very simply, rotation quantities are analogous to translation (linear movement) quantities. Thus there are rotational displacements, velocities and accelerations. All can be 1- 2- or 3-dimensional, just as in translation. A rotation vector is oriented along the axis of rotation; its length denotes its magnitude. Angular displacement, velocity and acceleration are often represented, respectively, by the symbols (or words) theta, omega and alpha.
Rotation dynamics involve energy, momentum, an equivalent to force called torque or moment, and an equivalent to mass called moment of inertia (often represented by I).
Torque about some reference point (e.g., a point on a rotation axis) can be obtained by applying a force oriented at right angles to the axis and applied at some displacement from the reference point. Torque = the cross-product of force and the displacement of the point of force application from the reference point.
The moment of inertia I represents the torque required to induce a unit angular acceleration of a given massive body. In the simplest body (a single mass M located a distance R from the rotation axis), I = M*R^2. For real bodies, I is a 3x3 matrix, each of whose elements is an integral of all the infinitesimal mass particles times the square of its distance from a reference point measured along particular axes.
Angular momentum is equal to torque * time, or to I * omega.
Rotational energy = torque * theta (angle through which torque is applied) or to 0.5 * I * omega^2.
I don't know the construction of your wheel, but if all the mass were concentrated at one radius R (i.e., the mass is all in a very thin rim), I (about the normal rotation axis) = M*R^2 just as in the simplest case described above. If it's a constant-thickness disk it's 0.5*M*R^2. See the ref.

Answer 2

♣ a new eternal engine, isn’t it? Well, inertia moment = 0.5m*R^2; you may address to me directly; I’m vice-president of Nobel Prize Comity. Just bribe me!