sqrt4x+12-12=0
please help
2007-06-16 05:58:29 · 5 answers · asked by Bianca B 1 in Science & Mathematics ➔ Mathematics
Is (4x+12-12) all under the sqrt?
If so, square both sides to get 4x+12-12=0
4x=0
x=0
If only (4x+12) is under the root, add 12 to both sides first to get sqrt(4x+12)=12
square both sides to get 4x+12=144
4x=132
x=33
2007-06-16 06:05:30 · answer #1 · answered by hrhbg 3 · 0⤊ 0⤋
well it depends on whats under the square root. im guessing its like sqrt(4x+12)-12=0 and if thats right:
sqrt(4x+12)=12 << move everything so that the sqrt is alone
square both sides
4x+12=144
4x=132
x=33
2007-06-16 13:05:53 · answer #2 · answered by Lizzy G 2 · 0⤊ 0⤋
Put the parentheses. If we take them as they are:
sqrt4x + 12 - 12 = sqrt4x = 2sqrtx
2007-06-16 13:03:54 · answer #3 · answered by Swamy 7 · 0⤊ 0⤋
sqrt 4x+12-120 ?
2007-06-16 13:09:21 · answer #4 · answered by deesnuts 5 · 0⤊ 0⤋
If you mean sqrt(4x+12-12)
sqrt(4x)
2*sqrt(x)
2007-06-16 13:02:11 · answer #5 · answered by bourqueno77 4 · 0⤊ 0⤋