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http://www.aqa.org.uk/qual/gceasa/qp-ms/AQA-MPC4-W-QP-JUN06.PDF

quetion 5a

i get 1-6x rather than y-6x
Any advice?

2007-06-16 04:53:02 · 1 answers · asked by efc_skillage 2 in Science & Mathematics Mathematics

5bi!!!! sorry think i wrote the wrong q number

2007-06-16 04:56:57 · update #1

1 answers

y^2-xy +3x^2 -5 = 0
When x = 1 we have
y^2 -y +3 - 5=0
y^2 -y -2=0
(y-2)(y+1)=0
So y= 2 or y = -1

2yy' -xy'-y +6x = 0
y'(2y -x) = y-6x
y' = (y-6x)/(2y-x)

2007-06-16 05:14:12 · answer #1 · answered by ironduke8159 7 · 0 0

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