A boy is half as old as his sister and two years younger than his brother. The sum of the ages of the three children is 34 years. How old is each child?
2007-06-16 03:53:12 · 4 answers · asked by CPUcate 6 in Science & Mathematics ➔ Mathematics
b1 = x
b2 = x + 2
s = 2x
x + (x + 2) + 2x = 34
4x + 2 = 34
4x = 32
x = 8
b1 = x = 8
b2 = x + 2 = 10
s = 2x = 16
2007-06-16 03:56:44 · answer #1 · answered by TychaBrahe 7 · 1⤊ 0⤋
age of boy = (34-2)/ 4
=8
boy = 8, sister = 16, brother 10
2007-06-16 10:57:16 · answer #2 · answered by pbtham 2 · 0⤊ 0⤋
Let the ages be x,y,z So A.T.Q. ,x+y+z+34,x=y/2 ,z=x+2 Solving we get, x = 8,y = 16 ,z = 10
2007-06-16 11:00:53 · answer #3 · answered by niti 2 · 0⤊ 0⤋
I love these! If tghe age of the boy is x, then the sister is 2x and the brother is x+2. Thus:
x + 2x + x+2 = 34
4x = 32
x=8
2007-06-16 10:55:56 · answer #4 · answered by Mark S, JPAA 7 · 0⤊ 0⤋