what is the radius of the sphere whose volume is 330 cubic meters?
2007-06-15 23:29:11 · 6 answers · asked by planetmath 1 in Science & Mathematics ➔ Mathematics
(4/3).π.r ³ = 330
r³ = (330 x 3 / 4) / π
r = 4.29 m
2007-06-16 04:51:42 · answer #1 · answered by Como 7 · 0⤊ 0⤋
Volume of a sphere +4/3 II r3 =330 Cm
Hence r = Cube root of 330 x 3 II / 4
2007-06-15 23:48:18 · answer #2 · answered by Joymash 6 · 0⤊ 0⤋
volume of sphere = volume of water displaced. 4/3 pi r^2 = pi R^2h the place r = radius of sphere = 3 cm, R = radius pf cylinder = 6 cm and h = height of water raised. so 4/3 × 3^3 = 6^2 × h fixing h = a million cm ----selection (a million)
2016-11-25 00:05:45 · answer #3 · answered by ? 4 · 0⤊ 0⤋
V=4/3pi r^3=330 Pi=3.14
r^3=78.78 r (radius of sphere )= 4.28 meters
2007-06-16 01:56:42 · answer #4 · answered by gamal 2 · 0⤊ 0⤋
The volume V of a sphere is 4*pi*r^3 / 3.
So r^3 = 3*V / (4*pi)
So r is the cube root of (3*V / (4*pi).
So in this case that's r = cube root of 990 / (4*pi).
Now you can use your calculator!
2007-06-15 23:36:59 · answer #5 · answered by tsr21 6 · 0⤊ 0⤋
V = (4/3)πr³
V(3/4) / π = r³
r = [V(3/4) / π]^(1/3)
r = [330(3/4) / π]^(1/3) meters
2007-06-15 23:37:23 · answer #6 · answered by S. B. 6 · 0⤊ 0⤋