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2007-06-15 22:42:32 · 5 answers · asked by Anonymous in Science & Mathematics Physics

5 answers

If you meant 60mph, we can work it out this way.

60 miles = 60 x 5280 feet = 316800 feet per hour

Dividing by 3600 we get 88 feet / sec.

Acceleration due to gravity is 9.81 m/sec which is 9.81 x 3.28 = 32.18 ft/sec (1.00000 Meter = 3.28084 Feet)

Using the formula, v = u + at

we can write 88 = 0 + 32.18t or

t = 88/32.18 = 2.73 secs

2007-06-15 23:18:29 · answer #1 · answered by Swamy 7 · 1 1

The terminal velocity of a skydiver in a normal free-fall position with a closed parachute is about 195 km/h (120 mph or 54 m/s). This velocity is the asymptotic limiting value of the acceleration process, since the effective forces on the body more and more closely balance each other as it is approached. 50% of terminal velocity is reached after about 3 seconds, while it takes 8 seconds to reach 90%, 15 seconds to reach 99% and so on.

(So it's about 3 seconds)

2007-06-15 22:48:05 · answer #2 · answered by leedsmikey 6 · 0 1

On earth acceleration is 10 metres per second per second.
This means that in one second the speed has gone up to 10 m/s, in 2 seconds it is 20m/s, 3seconds...30m/s etc.

30m/s = 108 km/hour =67.5 mph.

So it takes less than 3 seconds to reach 60mph.

You could say :
Falling brick...0-67.5 in 3 seconds flat. Eat your heart out Ferrari.
Exact 0-60 time is 2.73 seconds.

2007-06-15 22:48:10 · answer #3 · answered by Anonymous · 0 1

it depends on which planet or location you are talking about. On earth, simple estimation is 3 secs based on earths gravity.

Incidentally, i saw an advert for a car that can do this ( 0-60 in 3secs ). Driving upwards (uphill) would make this car standstill ?

2007-06-15 23:21:32 · answer #4 · answered by Moron 1 · 0 2

32f pr sec per sec
fancy math symbols here
2.9 secs

2007-06-15 22:54:58 · answer #5 · answered by Anonymous · 0 1

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