If you meant 60mph, we can work it out this way.
60 miles = 60 x 5280 feet = 316800 feet per hour
Dividing by 3600 we get 88 feet / sec.
Acceleration due to gravity is 9.81 m/sec which is 9.81 x 3.28 = 32.18 ft/sec (1.00000 Meter = 3.28084 Feet)
Using the formula, v = u + at
we can write 88 = 0 + 32.18t or
t = 88/32.18 = 2.73 secs
2007-06-15 23:18:29
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answer #1
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answered by Swamy 7
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The terminal velocity of a skydiver in a normal free-fall position with a closed parachute is about 195 km/h (120 mph or 54 m/s). This velocity is the asymptotic limiting value of the acceleration process, since the effective forces on the body more and more closely balance each other as it is approached. 50% of terminal velocity is reached after about 3 seconds, while it takes 8 seconds to reach 90%, 15 seconds to reach 99% and so on.
(So it's about 3 seconds)
2007-06-15 22:48:05
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answer #2
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answered by leedsmikey 6
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On earth acceleration is 10 metres per second per second.
This means that in one second the speed has gone up to 10 m/s, in 2 seconds it is 20m/s, 3seconds...30m/s etc.
30m/s = 108 km/hour =67.5 mph.
So it takes less than 3 seconds to reach 60mph.
You could say :
Falling brick...0-67.5 in 3 seconds flat. Eat your heart out Ferrari.
Exact 0-60 time is 2.73 seconds.
2007-06-15 22:48:10
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answer #3
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answered by Anonymous
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it depends on which planet or location you are talking about. On earth, simple estimation is 3 secs based on earths gravity.
Incidentally, i saw an advert for a car that can do this ( 0-60 in 3secs ). Driving upwards (uphill) would make this car standstill ?
2007-06-15 23:21:32
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answer #4
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answered by Moron 1
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32f pr sec per sec
fancy math symbols here
2.9 secs
2007-06-15 22:54:58
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answer #5
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answered by Anonymous
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