the time, T minutes, it takes an oil heater to heat a school hall is directly proportional to the volume of oil, V litres, in the oil heater
When V=150, T=650
Find T when V=558
2007-06-15 22:28:56 · 6 answers · asked by Twista-Adzy 2 in Science & Mathematics ➔ Mathematics
We know… T=F(V) (data)
===> T= KV …(1) Where K=numeric constant in minutes/liter
Later we replace V=150 and T=650 in (1):
650 = K(150) ===> K=13/3
Then the final function is:
T= F(v) = 13V/3 ……(2)
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When V=558, we have in (2)
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T = (13x558)/3 = 2418 minutes.
2007-06-15 23:00:43 · answer #1 · answered by CHARTIGER 2 · 0⤊ 0⤋
T=kV
whenT=650,V=150
650=kx150
k=13/3
T=13/3V
when V=558, V=?
T=13/3x558=13x186= 2418.minutes
2007-06-15 23:20:57 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Time dir. propor. to Volume ==> T = kV, with k = the proportionality constant, so:
650 = T = kV = k150 ==> k = 650/150 = 13/3
Thus T = (13/3)*558 = 13*186 = 2,418
Regards
Tonio
2007-06-15 22:40:25 · answer #3 · answered by Bertrando 4 · 0⤊ 0⤋
T/V = 650/150
If V=558
then T= 650/150 x558
=2418
or 2418 minutes
2007-06-15 22:39:32 · answer #4 · answered by sweet n simple 5 · 0⤊ 0⤋
T = kV
650 = 150 k
k = 65/15 = 13/3
T = (13/3).(558)
T = 13 x 186
T = 2418 minutes
T = 241.8 h
T = 40.3 h
T = 40h 18 mins
2007-06-16 04:39:53 · answer #5 · answered by Como 7 · 0⤊ 0⤋
150x= 650x
V = 558 =3.72(150)
x=3.72
T=3.72(650)
2007-06-15 22:37:48 · answer #6 · answered by Anonymous · 0⤊ 0⤋