solve
2
divide line
9
+
10
divide line
39
=
3
solve it please
2007-06-15 22:11:50 · 6 answers · asked by Twista-Adzy 2 in Science & Mathematics ➔ Mathematics
my mistakes sorry
the 9 is meant to be a "q" and the 39 is meant to be a "3q" sorry
2007-06-15 22:24:05 · update #1
well done to those above with the answer 16/9 i thought it was wrong but when you transpose it , it works out correct .
I suppose that q = 1.77rec is also correct
2007-06-17 04:01:58 · answer #1 · answered by mark the spark 4 · 0⤊ 0⤋
2/q +10/3q = 3
Multiply the whole equation by 3q to get rid of the fractions. SO you have:
6 +10 =9q
So 9q =16
q = 16/9
2007-06-16 05:38:39 · answer #2 · answered by Anonymous · 0⤊ 0⤋
2 / q + 10 / q = 3
X by 3q:-
6 + 10 = 9q
9q = 16
q = 16 / 9
2007-06-17 02:52:32 · answer #3 · answered by Como 7 · 0⤊ 0⤋
so the problem is: 2/q+10/3q=3
multiple everything with 3q then
2/q*3q+10/3q*3q=3*3q =>
=> 6 + 10 = 9q =>
=> 16=9q =>
=> q=16/9
2007-06-16 07:57:21 · answer #4 · answered by Konstantinos P 2 · 0⤊ 0⤋
Well...
times everything my 9 to form:
2 + 10 DIVIDE LINE 39 = 27
then times everything by 39 to form:
78 + 10 = 1053
88 = 1053
Wha? There were no unknowns in the equation!!!
2007-06-16 05:19:48 · answer #5 · answered by รզlεսռց ☆ 6 · 0⤊ 0⤋
2/q + 10/3q=3
you can cross multply this to get
6q+10q/3q^2=3
Then if you multiply both sides by 3q^2 you get-
16q= 3 + 3q^2
Rearrange this and you get- 3q^2 - 16q + 3 = 0
then you just need to factorise this to get-
q= -b (+ or -) sq root b^2 – 4ac/2a
q= 16 (+ or -) sq root 256- (4 x 3 x 3)/ 2 x 3
q= 16 (+ or -) sq root 256- 36/ 6
q= 16 (+ or -) sq root 220 / 6
So q= 16+ sq root 220 / 6 or q= 16- sq root 220/6
Therefore q= 5.14 or q= 0.19
2007-06-16 07:54:23 · answer #6 · answered by Anonymous · 0⤊ 0⤋