Math help! Linear equations.?

Question

Find the equation of the line

The line passes thru (7,2) and the y-intercept is 3.

Thank you

Answer 1

Simply

y = mx + b, m is slope, b is y intercept.


x +7y - 21 = 0.

Answer 2

The standard slope/y-intercept linear equation is
y = mx + b
where m = slope
b = y-intercept

Since we know that b = 3,
our initial equation is
y = mx + 3
Our goal now is to find m or the slope
By substituting the value in our point (7,2), we can find m
y = mx + 3
2 = m(7) + 3
2 = 7m + 3
2-3 = 7m + 3 - 3
-1 = 7m
-1/7 = 7m/7
-1/7 = m
m = -1/7
Therefore our equation of the line is
y = -1/7x + 3

Answer 3

Equation of line: y= mx+c, m=gradient, while c denotes the constant (obtained when x=0)

y-intercept is 3, therefore, constant=3.
The line will pass through the two points: (7,2) and (0,3) (y-intercept)
Hence, gradient= (2-3)/(7-0)
= -1/7

Now that you have the gradient and the constant, subsitute their values into the equation.
Therefore, the equation of the line would be: y= (-1/7)x+ 3

Hope this is of help! :)

Answer 4

quickest way is slope-intercept form.

y = mx + b, m is slope, b is y intercept.

you know it passes through (0,3) and (7,2).
so the slope m = (2 - 3)/(7 - 0)
= -1/7.

so you've got

y = -1/7x + 3, simplifying to
7y = -x + 21 or
x +7y - 21 = 0.

Answer 5

Points on line are (7,2) and (0 ,3)
m = (3 - 2) / (0 - 7)
m = - 1/7
y - 2 = (-1/7).(x - 7)
y = (-1/7).x + 3

Answer 6

x+7y-21=0