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lim x^7 cos (9/x)
x->0
if the limit exists

2007-06-15 18:49:50 · 4 answers · asked by chimstr 1 in Science & Mathematics Mathematics

4 answers

Limit is zero.

0^7 = 0
And cos(oo) will be a value between -1 and 1. Times 0, 0.

2007-06-15 19:00:46 · answer #1 · answered by ayante01 3 · 1 0

Even B is right. The maximum value the cosine function can assume is 1 and its minimum is -1. So cos (9/x) would oscillate between those two values, while lim x ---> 0 of x^7 would increasingly approach 0 as a limit. The entire limit evaluates to max = 0 * (1) = 0 and min = 0 * (-1) = 0. Guess that leaves little room for any other value for the limit.

2007-06-16 02:33:00 · answer #2 · answered by MathBioMajor 7 · 0 0

The limit is zero. The cosine is a bounded periodic function. and x^7 rapidly approaches zero.

2007-06-16 01:54:03 · answer #3 · answered by Anonymous · 1 0

limit is 0.

2007-06-16 02:05:01 · answer #4 · answered by ironduke8159 7 · 0 0

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