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in a poll of married couples, abt 79% of the men and 55% of the women were employed outside home..if 39%of the couples, both husband and wife worked outside home..find the probability that in a randomly selected couple, either husb or wife works outside home..
well i did solve it but the answer i get doesnt match wit the choices given:
a)56
b)12
c)16
d)18
e)24
...

2007-06-15 18:26:52 · 9 answers · asked by Anonymous in Science & Mathematics Mathematics

9 answers

a

79%- 39% = 40% where only the man works
55% - 39% = 16% where only the woman works

40% + 16% = 56% where only the man or only the woman works.

2007-06-15 18:31:34 · answer #1 · answered by Anonymous · 3 0

Event A= husband works
Event B= wife works

Now, P(A)= 79%
P(B) = 55%
and, P(A intersection B) = 39%

so, P(A union B) = P(A) + P(B) - P(A union B)
=(79+55-39)% = 95%

we need to find the probablity in which either event A or Event B occurs but at the same time both don't occur together

So, required probablity= P(A union B) - P(A intersection B)
=(95-39) % = 56%

so, the required probability is 56%.

2007-06-16 00:41:58 · answer #2 · answered by Happy 3 · 0 0

p(men work outside only ) =79-39=40%
p(women work outside only) =55-39=16%

p(either husb or wife works outside home)
=40+16
=56%#

2007-06-15 19:14:50 · answer #3 · answered by jackleynpoll 3 · 0 0

Well, that would mean that 39% of both men and women work outside of the home and are married, so that would leave 16% of women and 40% of men, so 1/16 of women only work outside the home, and 1/4 of men, so, i don't know what you do next, but it should be 16, I guess.

2007-06-15 18:39:20 · answer #4 · answered by hybrid7wolf5 2 · 0 1

the answer is choice a. because

79%- 39% = 40% where only the man works
55% - 39% = 16% where only the woman works

40% + 16% = 56%

hence the answer is 56

2007-06-15 21:12:08 · answer #5 · answered by suresh r 3 · 0 0

let m be the probability that the man only works
let w be the probability that only the woman works
let b be the probability that man and woman work.

m+b = .79
w+b = .55
b = .39
so m = .4, w = .16
b+m+w = .95
if they mean EXCLUSIVE OR, m+w = .56, or answer a.
poorly stated problem.

2007-06-15 18:35:48 · answer #6 · answered by holdm 7 · 0 0

Probability has to be >= 79%.

2007-06-15 18:51:46 · answer #7 · answered by ironduke8159 7 · 0 0

hiya, how previous are you?.. whats the choose of an bf in such an urgency?.. please think of.. it is not a remember to take a determination on an impulse. anticipate somebody you will think of you may cope with. in any different case its going to be on utter failure and you will repend for all the life?.. are you a virgin?.. do you decide directly to loose your virginity with him?.. then you definately could think of greater heavily. those issues are somewhat severe and complicated. in case you had taken a incorrect determination it could have impression in all the life. it is out of journey. please be careful .. yet once you nonetheless choose one attempt your superb buddy between boys or somebody you comprehend properly(please tak cre to choose their character by myself, funds and ask your self comes after basically)

2016-12-08 10:38:18 · answer #8 · answered by ? 4 · 0 0

it's probably c)...although I only pondered it for a minute

2007-06-15 18:35:22 · answer #9 · answered by Anonymous · 0 0

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