find antiderivative f(x)= -x^2-e^-x?

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2007-06-15 18:11:24 · 4 answers · asked by echo 1 in Science & Mathematics ➔ Mathematics

It is : -x^3/3 + e^-x.

2007-06-15 18:17:41 · answer #1 · answered by Kilohn 3 · 0⤊ 0⤋

g(X)=-(1/3)x^3+e^-x

2007-06-16 01:18:23 · answer #2 · answered by Anonymous · 0⤊ 0⤋

(x^4)/4)e^-x

2007-06-16 01:15:34 · answer #3 · answered by MrPogi 3 · 0⤊ 1⤋

I = - â« xÂ² + e^(-x).dx
I = - (xÂ³ / 3 - e^(-x) ) + C
I = - xÂ³ / 3 + e^(-x) + C

2007-06-16 13:11:13 · answer #4 · answered by Como 7 · 1⤊ 0⤋