Pllleeeaaasseee answer this Physics problem - you get 12 pts.?

Question

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Here, the current flowing through the 8.45 ohms ressitor is 1.22 A.

What is the voltage through the battery?

I got 10.306 and the book says that the answer should be 103.6.

What is constant in this type of problem, the current or the voltage?

JUST LOOK AT THE PICTURE, DISREGARD THE QUESTION IN THE PICTURE. THAT'S THE WRONG QUESTION THE RIGHT ONE'S HERE IN YAHOO ANSWERS (THE ONE ON TOP), THANKS!

Answer 1

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Answer 2

This is much different than your word description.
(1.22 A)(8.45 Ω + 4.11 Ω) =
(1.22 A)(12.56 Ω) = 15.3232 V
(15.3232 V)/(17.2 Ω) = 0.89088 A
(15.3232 V)/(13.8 Ω) = 1.11038 A
1.22 A + 1.11038 A + 0.89088 A = 3.22126 A
(3.22126 A)(15 Ω + 12.5 Ω) =
(3.22126 A)(27.5 Ω) = 88.58466 V
88.58466 + 15.3232 = 103.90786 V ≈ 103.9 V

The difference between my answer and the book's may be due to the number of digits carried through the calculation. I didn't round until the end.

Answer 3

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Answer 4

the flux capasitor