Please answer this Physics problem (PLEEEEASSSEE!)?

Question

The current flowing through the 8.45 ohms resistor is 1.22 A, given the resistors in the drawing below:
How much current flows throughout the entire battery?

THe circuit is: SERIES from unknown voltage of battery to 15, 12.5, 8, 45, and 4.11 ohms. Between 12.5 to 8.45, the circuit splits into two further resistors, 13.8 and 17.2, then joins the circuit again just aftr 4.11 ohms.

Answer 1

The answer is: The current from the 62.46 volts battery is 1.714297 A.

1.22(8.45 + 4.11) = 1.22*12.56 = 15.32 32V
15.3232/(13.8 + 17.2) = 15.3232/31 = 0.494297 A
0.494297 + 1.22 = 1.714297 A

This current 1.7143 flows through 15+ 12.5 =27.5 ohm resister and then divides into two parts (1.22A and o.4943A)
The voltage drop across 27.5 is 27.5*1.7143 = 47.14 V
add this to voltage drop across the parallel section (15.32V)
47.14+15.32 = 62.46V

The circuit is as below: Numbers are resistance values.
V is the voltage source. There are two current loops. First loop consists of voltage source V and 15 ,12.5, 13.8 & 17.2 ohm resisters. The second loop is with 8.45, 4.11,17.2 and 13.8 resisters. The second loop could not be drawn closed due to constrain on uploading.

!--15---12.5-------8.45---
!....................!.....................................
!.................13.8...................................
v...................!.......................................
!.................17.2................................
!....................!...................................
!----------------------4.11---

Answer 2

if the resistors are in series then the current is the same throughout If you had a pic of the circuit I could help you better but if all resistors are in series the current is 1.22A.
resistors in parallel have the same voltage and different current. The current is found by the equation 1/(1/?+1/?+1/?......) If some are in series and some are in parallel then use the formula to figure out the resistance of the parallel resistors and treat that number as if it is one resistor in series

Answer 3

1.22(8.45 + 4.11) = 1.22*12.56 = 15.3232 V
15.3232/(13.8 + 17.2) = 15.3232/31 = 0.49430 A
0.49430 + 1.22 = 1.7143 A