4.42 g of Ammonuim phosphate were dissolved in 20.0 L of water. How many moles of ammonium does the solution contain?
2007-06-15 15:13:43 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
4.42 g of (NH4)3PO4 in 20 L
Molar mass of (NH4)3PO4 is 149.1
4.42g/149.1 = 0.0296 moles of (NH4)3PO4 in 20 L
However, the question is how many moles of NH4+ does the solution contain. The 20 L of solution contain 3 x 0.0296 moles or 0.0888 moles of NH4+. The molar concentration of NH4+ is 0.0888/20 or 0.00444 Moles of NH4+ per L.
2007-06-15 17:26:46 · answer #1 · answered by skipper 7 · 0⤊ 0⤋
The formula is (NH4)3PO4. Total up the molecular mass.
Divide 4.42 g by the molecular mass to get moles. Then divide the moles by 20.0L to get molarity.
2007-06-15 22:23:30 · answer #2 · answered by reb1240 7 · 0⤊ 0⤋
Molar Mass = 149.12g/mol
4.42 g/ 149.12 g/mol = 0.0296 mols
divide by 20 L to get molarity, if that is part of the question.
best regards.
2007-06-15 22:25:29 · answer #3 · answered by jason s 3 · 0⤊ 0⤋