I need help with physics please?

Question

The best leaper in the animal kingdom is the puma, which can jump to a height of 11.1ft when leaving the ground at an angle of 42degrees. With what speed, in SI units, must the animal leave the ground to leave the ground to reach that height?

Thanks sooo much

Answer 1

10.97 meters per second

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- kevin

actually, to get the significant figures right, I should have reported the answer to be 11m/s

Answer 2

Jeff's right. But I assume your interest isn't limited to the answer. Here is how you can find it.

1. 11.1 ft = 11.1 ft × 0.3048 m/ft = 3.3833 m.

2. Disregard horizontal components. Let v be the initial velocity sought. Vertical component of this velocity is v sin 42°. I think I can safely assume the angle is measured respect to ground, since "... can jump to a height of 11.1 ft WHEN LEAVING THE GROUND at an angle of 42°."

3. From kinematics, (v sin 42°)² = 2gh; then,

v = √(2gh) / sin 42° = 8.1432/0.669131 = 12.17 m/s.

Answer 3

You need to specify whether your angle is respect to the horizontal or the vertical. If it is with respect to the vertical, your speed is 11.0 m/s. If it is with respect to the horizontal, your speed is 12.2 m/s.