does anyone know how to solve this algebra problem?

Question

x=1/5y
3x+2y=26

you have to solve it with the substitution method

Answer 1

x=1/5y
3x+2y=26 substitute
3(1/5y)+2y=26
3/5y+2y=26
2 3/5y=26
13/5y=26
13/5y X (5/13)=26 X (5/13)
y=10

hope this helps!

Answer 2

Substitution Method

x = 1/5y- - - - - - - - -Equation 1
3x + 3y = 26- - - - - Equation 2
- - - - - - - - - -
Substitute equation 1 into equation 2

3x + 3y = 26

3(1/5y) + 2y = 26

3/5y + 2y = 26

3/5y + 10/5y = 26

13/5y = 26

5(13/5y) = 5(26)

13y = 130

13y / 13 = 130 / 13

y = 130 / 13

y = 10

Insert the y value into equation 1
- - - - - - - - - - -

x = 1/5y

x = 1/5(10)

x = 10/5

x = 2

Insert the x value into equation 1
- - - - - - - - - -

Check equation 1

x = 1/5y

2 = 1/5(10)

2 = 10/5

2 = 2

- - - - - - - -

Check equation 2

3x + 2y = 26

3(2) + 2(10) = 26

46 + 20 = 26

26 = 26

- - - - - - - - - --

Both equations balance

The solution set { 2, 10 }

- - - - - - - - - -s-

Answer 3

First we need to substitute x into the second equation.

Therefore,
3(1/5y) + 2y = 26
3/5y + 2y = 26
13/5y = 26
13=130y
y=130/13
y = 10

When y=1, x = 1/5 X 10
x = 2

Answer 4

x=1/5y
3x+2y=26
Put 1/5y from the 1st equation for x in the 2nd equation:
3(1/5y) + 2y = 26
2 3/5 y = 26
13/5 y = 26
y = 5/13*26= 10
x = 1/5 (10)= 2
x=2 and y = 10

Answer 5

First: substitute/replace (1/5)y with "x" in the 2nd equation.

2) 3x + 2y = 26
3[(1/5)y] + 2y = 26
(3/5)y + 2y = 26
(13/5)y = 26

*Divide both sides by 13/5 (when you move a term to the opposite side, always use the opposite sign).

(13/5)y/(13/5) = 26/(13/5)
y = (26/1)/(13/5)

Sec: rule - you can't divide fractions. multiply the 1st fraction with the reciprocal of the 2nd fraction.

y = (26/1)*(5/13)
y = 130/13
y = 10

Third: substitute 10 with "y" in the 1st equation.

1) x = (1/5)y
x = (1/5)(10)
x = 10/5
x = 2

Solution set: (2, 10)

Answer 6

Plug x in:

3(1/5y)+2y=26

Distribute:

(3/5)y+2y=26

Add Together:

(13/5)y=26

Divide both sides by (13/5):

y=10

Now plug y into original:

X=2

Answer 7

Yes. Or you can write like x-(1/5)y=0, and solve the wo equations.

3x + 2y = 26
Substitute => (3/5)y +2y = 26

3y + 10y = 130

13y = 130

y = 10

So x = (1/5)*10

x = 2

Answer 8

just put (1/5y) in where "x" is in the bottom equation.
You get 3(1/5y) + 2y = 26.
Which is 3y/5 + 2y = 26...
3y/5 + 10y/5 = 26...
13y/5 = 26
y = 10
Therefore x = 2

Answer 9

(3*1/5y)+2y=26 1 1/2y+2y=26 3 1/2y=26 y=7.43 I think?

Answer 10

B/2 = -7 + B multiply the two aspects with the aid of two (*2)B/2 = 2(-7+B) simplify B = -14 + 2B subtract 2B from the two aspects B (-2B) = -14 + 2B (-2B) simplify -B = -14 divide with the aid of a adverse to isolate your variable -B/- = -14/- simplify B = 14 --------------------------------------... to verify: positioned your fee for B this is 14 in the equation the place B is placed 14/2 = -7+14 7 = 7 and the solutions are an identical so that's actual