6(y-2)+5= -13
2007-06-15 06:11:24 · 10 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
6(y - 2) + 5 = -13
6y - 12 + 5 = -13
6y - 7 = -13
6y = -6
y = -1
Check: 6(-1 - 2) + 5 = 6(-3) + 5 = -18 + 5 = -13
First I applied the distributive property. Then I combined like terms on the left side. Finally, I isolated the variable using simple algebra.
2007-06-15 06:13:23 · answer #1 · answered by DavidK93 7 · 1⤊ 0⤋
First you have to distribute the 6 into the parenthases. That makes it 6y-12+5= -13. Then you combine the like terms which are the numbers. That leaves you with 6y-7= -13. To get rid of the -7 on the left side, you have to add a positive 7 to both sides to make the negative 7 zero. That is 6y= -6. From here, you divide both sides by 6, so, y is equal to -1.
2007-06-15 06:20:41 · answer #2 · answered by Josephine T 1 · 0⤊ 0⤋
Distributive law first...
6(y-2)+5= -13
6y -12 +5 =-13 combine terms
6y -7 =-13
add 7 to both sides
6y -7 +7 = -13 +7
6y= -6
divide 6 on both sides
6y/6 = -6/6
y= -1
2007-06-15 06:16:23 · answer #3 · answered by Invisble 4 · 0⤊ 0⤋
OK multiply 6*Y and 6*-2 to get 6Y-12+5+=-13
-12+5=-7 so 6Y-7=-13
add 7 to both sides to cancel out and isolate 6Y
Now 6Y=-6
divide both sides by 6 to isolate Y
y= -1
2007-06-15 06:18:51 · answer #4 · answered by Big B 2 · 0⤊ 0⤋
this question isn't too confusing, we'd desire to factorise. merely ask your self: what 2 aspects of sixty six upload to offer 17? nicely, component pairs of sixty six contain: 2 and 33, 6 and 11, 3 and 22. for sure 6 and 11 are the respond. So the factorisation is: (y - 11)(y - 6) = 0 y = 11 or 6 this is, until you probably did no longer merely omit the y there, and you certainly needed to factorise: y^2 - 17 + sixty six = 0 y^2 + 40 9 = 0 y^2 = -40 9 This has no actual answer, when you consider that we gained't have the sq. root of a adverse.
2016-12-13 03:47:27 · answer #5 · answered by wintz 4 · 0⤊ 0⤋
6y-12+5 = -13 (distribution)
6y - 7 = -13
6y = -6 (add 7 to both sides)
y = -1 (divide 6 from both sides)
2007-06-15 06:17:21 · answer #6 · answered by littlepeculiar13 2 · 0⤊ 0⤋
First, distribute the 6, so you get:
6y-12+5=-13
Then combine the -12 and 5, to get:
6y-7=-13
Then add 7 to both sides to isolate the variable:
6y=-6
Then divide both sides by 6:
6y/6=-6/6
The answers you get is:
y=-1
Now to check it, plug in -1 wherever you see an y.
2007-06-15 06:16:37 · answer #7 · answered by Anonymous · 0⤊ 0⤋
6y - 12 + 5 = -13
6y - 7 = -13
6y = -13 + 7
6y = -6
y = -6/6
y= -1
2007-06-15 06:34:57 · answer #8 · answered by mmm ssss 1 · 0⤊ 0⤋
6(y - 2) + 5 = -13
6(y - 2) = -13 - 5
6y - 12 = -18
6y = -18 + 12
6y = -6
y = -6/6
y = -1
2007-06-15 06:34:33 · answer #9 · answered by topsyk 3 · 0⤊ 0⤋
David is correct! And he explained it so well.
2007-06-15 06:15:22 · answer #10 · answered by amiari 3 · 0⤊ 0⤋