x: 8(2x - 3)+5=61
2007-06-15 06:02:43 · 8 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
8(2x - 3) + 5 = 61
8(2x - 3) = 61 - 5
8(2x - 3) = 56
2x - 3 = 56/8
2x - 3 = 7
2x = 7 + 3
2x = 10
x = 10/2 = 5
2007-06-15 06:08:23 · answer #1 · answered by topsyk 3 · 0⤊ 0⤋
8(2x - 3)+5=61
you need to distribute the 8 to the parenthesis ()
8 x 2x = 16x & 8 x -3 = -24
16x + -24 + 5 = 61 or 16x - 24 + 5 = 61
combine -24 and 5...
-24 + 5 = -19
16x + -19 = 61 or 16x - 19 = 61
change the sign of -19 to +19 and add to 61
16x + -19 = 61
+19 = + 19
16x = 80
see, the -19 + 19 = 0 but you don't have to write that.
divide by 16 on both sides to get the x by itself
16x = 80
/16 = /16
x = 5
I hope you understood
2007-06-15 06:19:29 · answer #2 · answered by Izzpuppy 5 · 0⤊ 0⤋
8(2x - 3) + 5 = 61
8(2x) - 8(3) + 5 = 61
16x - 24 + 5 = 61
16x - 19 = 61
16x = 61 + 19 = 80
16x / 16 = 80 / 16
x = 5
2007-06-15 06:10:22 · answer #3 · answered by Dan H 4 · 0⤊ 0⤋
8(2x - 3) + 5 = 61
*distribute*
16x - 24 + 5 = 61
*add*
16x -19 = 61
*add 19 to both sides*
16x = 80
*divide by 16*
x= 5
2007-06-15 06:10:13 · answer #4 · answered by Andrew F 2 · 0⤊ 0⤋
to solve for x means getting x by itself
multiply inside the parenthesis
16x-24+5=61
combine like terms
16X-19=61
add 19 on both sides
16x= 80
divide by 16
x= 5
2007-06-15 06:06:39 · answer #5 · answered by sellasell 3 · 0⤊ 0⤋
8(2x-3)+5=61
subtract 5 from both sides
8(2x-3)=56
divide both sides by 8
2x-3=7
add 3 to both sides
2x=10
divide both sides by 2
x=5
2007-06-15 06:09:16 · answer #6 · answered by Anonymous · 0⤊ 1⤋
16x - 24 + 5 = 61
16x = 80
x = 5
2007-06-15 22:31:56 · answer #7 · answered by Como 7 · 0⤊ 0⤋
x=5
8(2x-3)+5=61
16x-24+5=61
16x-19=61
16x=80
x=5
2007-06-15 06:11:19 · answer #8 · answered by Jeff 2 · 0⤊ 0⤋