algebraic expression help?

Question

hello everyone.. i think i got this right please let me know..

the sum of 3 consecutive odd intergers is 27

ok so since each odd interger is 1 larger than the previous interger i came up with

x + (x+2) + (x=4)=27 is this right?

Answer 1

yes, the three consecutive odds would be x, x+2, x+4 so
x+x+2+x+4=27
3x+6=27
3x=21
x=7
so the other two are 9,11

Answer 2

LOOK, SINCE ALL MULTIPLES OF 2 ARE EVEN, ADDING 1,3 AND OTHER ODD NOS TO THEM WILL MAKE THEM ODD, SO
LET THE 3 INTEGERS BE (2x+1), (2x+3), (2x+5)
HENCE, (2x+1)+ (2x+3)+ (2x+5)=27
6x+9=27
6x=27-9
6x=18
x=18/6
x=3

SUBSTITUTING x=3, the three nos are:

2x+1 = 2(3)+ 1 =6+1 = 7
2x+3 = 2(3) +3 = 6+3=9
2x+5= 2(3) + 5 = 6+5=11

CHECKING THE ANSWER,
7+9+11=16+11=27
YAY!!!

YOUR ANSWER IS WRONG BECAUSE, U TOOK x AS THE 1ST INTEGER WHICH MEANS THAT U DID NIOT MAKE x COMPULSARILY AN ODD NO.

Answer 3

1) x+1
2) x+3
3) x+5

Algebraic EQuation: x+1+x+3+x+5 = 27

First: combine "like" terms.

3x+9 = 27

Sec: subtract 9 from both sides (when you move a term to the opposite side, always use the opposite sign).

3x+9 -9 = 27-9
3x = 27-9
3x = 18 (divide both sides by 3).
3x/3 = 18/3
x = 18/3
x = 6

Fourth: substitute 6 with each "x" variable in the expressions.

a. x+1 = 6+1 = 7
b. x+3 = 6+3 = 9
c. x+5 = 6+5 = 11

7, 9, 11

Answer 4

Since 2x is an even integer
2x + 1 is odd

Then

(2x + 1) + (2x + 3) + (2x + 5) = 27

Combine terms

6x = 18

x = 3

(2x + 1) = 7

(2x + 3) = 9

(2x + 5) = 11

11 + 9 + 7 = 27
.

Answer 5

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