Need someone to check my math: molecular weight of compound 602.58. Need to make 200uM at 2.0uL.?

Question

So, I read that 100uM at 4uL = 0.4 nmol. I want to make 0.4 nmol with 200 uM at 2.0 uL. I came to 0.121mg/mL. Does this sound correct?

Answer 1

Yes.

Answer 2

Despite the strange wording of your question, you do have the right answer.

I presume you were asking how to make a 200 micromolar solution of a compound with a molecular weight of 602.58 g.

In terms of mass, this is 200x10^-6 mol/L * 602.58 g/mol = 0.1205 g/L or mg/mL.