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f(x)=x(x+2)^3(2x+3)^2

2007-06-15 03:28:37 · 2 answers · asked by taz073188 1 in Science & Mathematics Mathematics

2 answers

Set each factor equal to zero and solve.
x = 0
x + 2 = 0
or 2x + 3 = 0

So the zeros are x=0, x = -2, and x = -3/2

2007-06-15 03:32:24 · answer #1 · answered by MsMath 7 · 1 0

This is extremely easy, f is a polynomial and is already factored. All you have to do is find the zeros of each factor, that is, solve the simple equations

x = 0
x + 2 = 0
2x + 3 = 0

So, the zeros are 0, -2 and -3/2.

2007-06-15 03:36:14 · answer #2 · answered by Steiner 7 · 0 0

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