2007-06-15 03:07:34 · 5 answers · asked by andra s 1 in Science & Mathematics ➔ Mathematics
2(x-3)/3-x-2/4=1 (distribute the 2, and 2/4=1/2)
(2x-6)/3-x-1/2=1 (multiply all by 3)
2x-6-3x-3/2=3 (simple reconfiguration)
2x-3x-6-3/2=3 (combine x factors and add 6 to both sides)
-x-3/2=9 (multiply all by 2)
-2x-3=18 (add 3 to both sides)
-2x=21 (divide both sides by -2)
x= -10.5
or
2(x-3)/3-x-2/4=1 (multiply all by 3 and 2/4=1/2)
2(x-3) - 3x - 3/2 =3 (multiply all by 2)
4(x-3) -6x -3 =6 (distribute the 4 and add 3 to both sides)
4x -12 -6x = 9 (combine x factors and add 12 to both sides)
-2x =21 (divide both sides by -2)
x= -10.5
2007-06-15 03:31:39 · answer #1 · answered by jeremy s 1 · 0⤊ 0⤋
Always start by clearing fractions. The way to clear them is to multiply everything by the LCM, in this case, 12.
Should be left with 8(x-3)-12x-3*2=12 Clear ()
Then 8x-24-12x-6=12 Combine like terms,
-4x-30=12
-4x=42
x=-42/4=21/2
2007-06-15 10:21:23 · answer #2 · answered by Freddie 2 · 0⤊ 0⤋
the above left side can be simplified to
(8x-24)/(3 - x - 2) which does not = 1
2007-06-15 10:12:41 · answer #3 · answered by GTB 7 · 0⤊ 0⤋
(2x -6)/3 -x -1/2=1
2x-6-3x-3/2=3
4x-12-6x-3=6
-2x-15=6
2x= -11
x= -11/2= - 5.5
2007-06-15 10:15:28 · answer #4 · answered by Anonymous · 0⤊ 0⤋
12-12x-8=2x-6
now solve?
2007-06-15 10:13:05 · answer #5 · answered by Amitabh S 3 · 0⤊ 0⤋