an ice cube (mass - 1.0kg) slides down an inclined ramp with an acceleration of 4.0 meters per second. Ignoring friction, how much force is pulling the ice cube down from the ramp?
2007-06-15 02:58:22 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Physics
Force = (mass)(acceleration)
F = m.a
F in Newton
m in kilograms
a in meters square per second
there is no acceleration with dimension meters per second. but, let say you mistype the dimension, we can solve the problem like this:
mass = 1 kg
acceleration = 4 meters square per second
F = (1)(4)
F = 4 Newtons
2007-06-15 03:09:14 · answer #1 · answered by oRigin 2 · 0⤊ 0⤋
The equation for force is F=ma. In this situation you know m, mass and you know a, acceleration. Mass is equal to 1 kg and accel. is equal to 4/s^2. So the force would be 1 kg * 4m/s^2=4 Newtons.
2007-06-15 03:06:36 · answer #2 · answered by big_leehi7 1 · 0⤊ 0⤋
F = ma
F = (1 kg)(4 m/s^2)
F = 4 N
2007-06-15 03:01:21 · answer #3 · answered by yeeeehaw 5 · 0⤊ 0⤋
A skydiver falls at a steady speed after his/her parachute opens. If their complete mass (adding chute) is ninety kg, what's the drive of drag on him/her? _90 x nine.eighty one = 882.nine N..................ans coefficient of friction = Frictional drive / Normal response ?s = 12 / ( 6 * nine.eighty one) = zero.204..................ans ?k = 10 / (6 * nine.eighty one) = zero.17 .....................ans
2016-09-05 17:20:50 · answer #4 · answered by ? 4 · 0⤊ 0⤋
F = ma
mass is 1.0 kg;
a = 4.0 meters / second squared (your unit is incorrect)
you can figurre it from here.
2007-06-15 03:02:06 · answer #5 · answered by GTB 7 · 0⤊ 0⤋