I have a maths problem?

Question

How do i factorise 18a+15b-20bc-24ac.

Is it a) (6a+5b)(3-4c)
b) (6a+5b)(4-3c)
c) (6a-5b)(3-4c)
d) (6a-5b)(3+4c)

Answer 1

rearranging we have
18a-24ac+15b-20bc

factoring we 6a in the first two and 5 b in the last two
6a(3 - 4c)+5b(3 - 4c)

factoring 3 - 4c we have
(6a + 5b) (3 - 4c)

A

Answer 2

With a multiple choice question like this one, you don't even have to know how to factorise. Just try each one in turn.

So for (a) (6a+5b)(3-4c) = 18a+15b-24ac-20bc.
Bingo, got it in one, the answer is (a).

Answer 3

its A.
(6a+5b)(3-4c)

you use the f.o.i.l. method you multiply first, outer, inner, last
for example...
6a times 3 =18a First
6a times -4c=-24ac outer
5b times 3=15b inner
5b times-4c=-20bc last

so you get 18a+15b-20bc-24ac
which is what u had in the beginning

Answer 4

18a + 15b - 20bc - 24ac =

Rearrange

18a - 24ac + 15b - 20bc =

Group factor

(18a - 24ac) + (15b - 20bc) =

6x(3 - 4c) + 5b(3 - 4c) =

(6a + 5b)(3 - 4c)

The answer is A

- - - - - - - - -s-

Answer 5

Its (a) (6a+5b)(3-4c)

Multiply term by term: 6a . 3 (+)or(-) 6a.4c & then 5b.3 (+) or (-) 5b.4c .

By the way the guy who answerd 1st Rahhot or whatever is a moron.

Answer 6

18a+15b-20bc-24ac

18a-24ac +15b-20bc

6a(3-4c) +5b(3-4c)

(6a+5b)(3-4c)

so answer is a

Answer 7

It's a matter of multiplying:
Answer a) results in: 18a+15b-24ac-20bc
b) 24a+20b-18ac-15bc
c) 18a-15b-24ac+20bc
d) 18a-15b+24ac-20bc

Since you're allowed to swap the aswer is A)

Answer 8

(3-4c)(6a+5b)

Answer 9

The correct answer is "a".
If you multiply the two terms, you can see the equivalence.

Answer 10

i've forgotten how to factor already, but if i were you i would just expand all the given choices and see which one yields the term to be factored. it's pretty easy.