i have up until x=+ or - the square root of 34 all over 2 but its not even
2007-06-14 15:19:09 · 10 answers · asked by Gorilla Unit 1 in Science & Mathematics ➔ Mathematics
USING THE QUATRATIC EQUATION
2007-06-14 15:25:34 · update #1
x²+5x-6=0
(x+6)(x-1)=0
x+6=0
x=-6
x-1=0
x=1
x=1, -6
you could use the quadratic formula
x=(-5±√(5²+4*6))/2
x=(-5±√(25+24))/2
x=(-5±√49)/2
x=(-5±7)/2
x=(-5-7)/2=-12/2=-6
x=(-5+7)/2=2/2=1
x=1, -6
I think that instead of 5^2 you did 5*2 so you got 10+24=34 rather than 25+24=49 inside the radical.
2007-06-14 15:26:30 · answer #1 · answered by yupchagee 7 · 1⤊ 1⤋
Solve the "x" variable... x^2+5x-6 = 0
First: factor - multiply the 1st & 3rd term to get -6. find two numbers that give you -6 when multiplied & 5 (2nd term) when added/subtracted. the numbers are (-1 & 6). rewrite the expression with the new middle terms.
x^2 - 1x + 6x - 6 = 0
SEc: group "like" terms & factor both sets of parenthesis.
(x^2 - 1x) + (6x - 6) = 0
x(x-1) + 6(x-1) = 0
(x-1)(x+6) = 0
Third: solve the "x" variables - set both parenthesis to "0"
a. x-1 = 0 (add 1 to both sides - when you move a term to the opposite side, always use the opposite sign).
x-1+1 = 0+1
x = 1
b. x+6 = 0 (subtract 6 from both sides).
x+6-6 = 0-6
x=-6
Solutions: -6, 1
2007-06-14 22:28:58 · answer #2 · answered by ♪♥Annie♥♪ 6 · 0⤊ 1⤋
x^2 + 5x - 6 = 0
+6 +6
x^2 + 5x = 6 (5/2)^2 = 6.25
+6.25 +6.25
x^2 + 5x + 6.25 = 12.25
Quadratic Formula:
x = -5 + or - the square root of 5^2 -4 (1)(6.25) / 2(1)
x = -5 + or - 25 -4 (6.25) / 2
x = -5 + or - 25 - 25 / 2
x = -5 + or - 0 / 2
x = -5 + or - the square root of 0 / 2
x = -5 + 0 / 2 = 0 or x = -5 - 0 / 2 = 0
I think that x = 0, but I am not sure
2007-06-14 22:31:55 · answer #3 · answered by maosportz 2 · 0⤊ 1⤋
By Factoring (reverse F.O.I.L. method)
x²+5x-6=0
(x-6)(x+1)
Then set each to equal 0
(x-6)=0
(x+1)=0
and solve those to get
6 and -1
2007-06-14 22:29:43 · answer #4 · answered by Anonymous · 0⤊ 1⤋
x^2 + 5x - 6 = 0
factor
(x + 6) (x - 1) = 0
x = -6 or 1
2007-06-14 22:22:44 · answer #5 · answered by 7 · 0⤊ 1⤋
x² + 5x - 6 = 0
factor
(x + 6)(x - 1) = 0
x = 1, x = -6
.
2007-06-14 22:22:18 · answer #6 · answered by Robert L 7 · 0⤊ 1⤋
x2 + 5x - 6 = 0
(x+6)(x-1)=0
Therefore, x+6=0, x=-6
And x-1=0, x =1
So, x=-6 or 1
2007-06-14 22:24:30 · answer #7 · answered by maverick 2 · 0⤊ 1⤋
(x + 6)(x - 1) = 0
x = -6 or 1
2007-06-14 22:22:53 · answer #8 · answered by cheeseballer 3 · 0⤊ 1⤋
x=2 or x=3
thats class algebra there
2007-06-14 22:22:21 · answer #9 · answered by Steve A 2 · 0⤊ 2⤋
2 or 3
When you simplify this, it becomes: (x+3)(x+2).
2007-06-14 22:23:07 · answer #10 · answered by Anonymous · 0⤊ 3⤋