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Eight times the sum of a number and -168 amounts to -64. Find the number.

13
-29
160
-176

2007-06-14 15:18:09 · 10 answers · asked by Anonymous in Science & Mathematics Mathematics

10 answers

Numerical data: 8(x + (-168)) = -64

8(x -168) = -64

First: eliminate parenthesis - use Distribution.

8(x) + 8(-168) = -64
8x + (-1344) = -64
8x - 1344 = - 64

Sec: combine "like" terms - add 1344 with both sides (when you move a term to the opposite side, always use the opposite sign).

8x - 1,344+1,344 = - 64+1,344
8x = -64+1,344
8x = 1,280

Third: isolate "x" - divide both sides by 8.

8x/8 = (1,280)/8
x = (1,280)/8
x = 160

2007-06-14 15:39:22 · answer #1 · answered by ♪♥Annie♥♪ 6 · 1 0

First, write out the problem: 8(n -168)= -64

Simplify: 8(n -168)= -64 is the same as 8n -1344= -64

Divide 8n - 1344= -64 by 8, it gives you: n-168= -8

Add 168 to each side: n -168 + 168 =n, -8 + 168 =160

n = 160

2007-06-14 22:44:39 · answer #2 · answered by ? 2 · 0 0

8(x-168)= -64

-64/8=x-168

-8+168= answer 160

2007-06-14 22:40:08 · answer #3 · answered by Hilgy 2 · 0 0

Hi, you would first distribute the 8 to the n and -168
8(n-164)=-64

8n-1344=-64
+1344 +1344

8n=1280
Divide the 8

1280/8 =160

n=160

2007-06-14 22:26:35 · answer #4 · answered by Dogna M 4 · 0 0

let the number be x
According to the problem.
8(x-168)=-64
or,8x-1344= -64
or,8x= -64+1344=1280
or,x=1280/8
=160
The number is 160

2007-06-14 23:32:44 · answer #5 · answered by alpha 7 · 0 0

let x be the number
8x-168=-64 add 168 to both sides
8x=104 divide both sides by 8
x=13

2007-06-14 22:28:33 · answer #6 · answered by yupchagee 7 · 0 1

Answer is 160.
160 + -168 = -8
8 * -8 = -64

2007-06-14 22:26:57 · answer #7 · answered by krahjerdi 2 · 0 0

8 * (x + (-168) ) = -64
8 * (x - 168) = -64
x - 168 = -8
x = 160

2007-06-14 22:21:27 · answer #8 · answered by      7 · 0 0

8 ( x - 168) = -64

8x - 1344 = -64

8x = 1280

x = 160

160 is your answer.

2007-06-14 22:21:02 · answer #9 · answered by de4th 4 · 0 0

I already worked this problem (with different numbers) for you earlier in another question.
If you don't want to learn, I don't want to waste my time on you ☺

Doug

2007-06-14 22:22:38 · answer #10 · answered by doug_donaghue 7 · 1 0

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