If the perimeter of an isoceles triangle is 71 cm and one of the sides is 22 mc, what are all the possible lengths of other 2 sides?
It was on the math a regents. help?
2007-06-14 14:26:15 · 4 answers · asked by moo 3 in Science & Mathematics ➔ Mathematics
An isoceles triangle has two of its sides equal.
Let the base be c and the other sides a,a.
2a+c=71
2a+22=71 if the base is 22 cm
2a=71-22=49
a=24.5
The sides are 24.5,24.5 and 22
Other possibility
2(22)+c=71
44+c=71
c=71-44=27
The sides are 22,22 and 27
2007-06-14 14:34:04 · answer #1 · answered by cidyah 7 · 0⤊ 0⤋
There are only 2 cases here.
1. The 22 cm side is not one of the sides that are equal.
or
2. It is one of the sides that are equal.
In case 1, the remaining 71-22 = 49 cm must be divided equally between the two sides so that each is 24.5 cm. Then the sides are 22, 24.5, and 24.5.
In case 2, the other equal side is also 22 cm long and the remaining side is 71 - 44 = 27 cm long.
Doug
2007-06-14 21:34:36 · answer #2 · answered by doug_donaghue 7 · 0⤊ 0⤋
2 possibilities - an isosceles has only 2 equal sides.
1) if the 'different' side is 22 cm then the equal sides total 49 cm. (71 - (2*22))
divide that by 2 to give 24.5 cm each.
2) If the 'equal' sides are 22 each then the other side is 71 - 44 = 27 cm.
2007-06-14 21:35:18 · answer #3 · answered by Ewan D 1 · 0⤊ 0⤋
isosceles has two sides the same, so the possibilities are
22 22 27
or
22 24.5 24.5
2007-06-14 21:30:08 · answer #4 · answered by tsr21 6 · 0⤊ 0⤋