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If you want to tackle a challenge factoring problem then I think you may find this one fun. First correct answer will get the 10.

Completely factor:

x^8 + x^7 + x^6 + x^5 + x^4 + x^3 + x^2 + x +1

2007-06-14 11:32:33 · 1 answers · asked by chancebeaube 3 in Science & Mathematics Mathematics

I should have pointed out that I was looking for non-Complex factoriztion, but if you want to factor to complex roots that would be fine, too. Not required to be best answer though...

2007-06-14 11:43:14 · update #1

1 answers

x^8 + x^7 + x^6 + x^5 + x^4 + x^3 + x^2 + x +1

(x^8 + x^7 + x^6 )+ (x^5 + x^4 + x^3) +( x^2 + x +1)

x^6(x^2 + x + 1) + x^3(x^2 + x + 1) + 1(x^2 + x + 1)

(x^2 + x + 1) (x^6 + x^3 + 1)

that's the furthest you can go

2007-06-14 11:51:19 · answer #1 · answered by      7 · 1 0

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