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In a zero gravity situation
#1 If you drop a ball does it drop?
#2 If it drops does it bounce back to the identical height?

2007-06-14 11:12:23 · 9 answers · asked by Anonymous in Science & Mathematics Physics

9 answers

Well, lets analyze this in a serious physics way..

1).. you can't drop a ball if there is no where to drop.
the word drop means there is a place where it will fall. if there is no gravity field, nothing will act on the ball to make it accelerate toward it!..hece the net force on it will be zero. as for w=mg, since g=0, and w=f..
f=0.. hence no force acting on it..

since a=f/m, and f=0 a=0.. where there is no acceleration there in force. then, if object is at rest, it will remain at rest. if its already in motion, it continue in motion, without being disturbed,.. as for the second question.

if you assume something bouncing, there must have been something that made it fall!..
hence accelertation downward.
as for bouncing back to identical height?.. only in a perfect elastic situation with the ball bounce back to its original height...

hope that helps..

2007-06-14 11:24:18 · answer #1 · answered by JAC 3 · 0 0

If you are not forcing the ball in any way then it shoud stay where it is. Zero gravity means zero gravitational force. Zero force =zero motion. However if you drop the ball here on earth and the coefficient of restitution between the ball and the ground is a perfect 1 (that means totally elastic) and there are no energy losses to air resistance or friction, the ball should return to exactly the same position. The acceleration of the ball to the ground is dependant on which planet you are standing on. For example, if you dropped an identical ball on the moon, it would travel a lot slower on its way to the surface as the mass of the moon is much les than the earth. This creates less gravity. For a fair test though, the experiment on earth would have to be undertaken in a vaccum (no air) as there is no air on the moon.

2007-06-14 11:20:29 · answer #2 · answered by ene 2 · 0 1

1) If theres no gravity then theres no force to make the ball drop so no. You would have to push it down and intertia would take it from there.
2) No gravity = No bounce. Assuming that you do push it down inertia would take it to the ground and it would bounce back with the same force, however, i would go beyound the point at which it was thrown from because there is no force to stop it from traveling on forever until another force acts upon it.

2007-06-14 11:18:06 · answer #3 · answered by FrozenFire 2 · 0 1

If you "let go" of a ball in zero gravity, its inertia will keep it from moving relative you to...

If you had a moving ball and it hit a stationary object with much greater mass in an inelastic collision, it would bounce off and its inertia would keep it moving at a constant rate in the same direction it bounced off, so in zero gravity, if an object is propelled and bounces back, it will pass its original location

2007-06-14 11:17:50 · answer #4 · answered by Mike 2 · 0 1

1.) Yes 2.) Velocity; measured in m/s, so it is a vector function. 3.) Distance-time graphs represent velocity functions; a uniform distance-time graph is linear; a non-uniform graph represents parabola, exponential, or other functions as the change is not constant. 4.) Yes, gravitation accelerates the object. 5.) 250/25 = 10 m/s 6.) y = 20 - 5x^2; y' = -10x; x = 2; velocity = -20 m/s 7.) a.) Displacement: 10*sqrt(5) - 22 meters; b.) 52 meters

2016-04-01 08:02:37 · answer #5 · answered by Anonymous · 0 0

Zero gravity means that; let goes, the ball doesn't move.

2007-06-14 11:15:50 · answer #6 · answered by Gene 7 · 1 1

If in zero gravity and you let it go, it should stay right where you let go of it unless you put a force on it.

2007-06-14 11:15:05 · answer #7 · answered by zippythewonderslugohio 4 · 3 1

If there's no gravity it wont drop, it will stay wherever you put it.

2007-06-14 11:15:44 · answer #8 · answered by Sunrayye 5 · 1 1

If no forces are acting on the ball, it won't move.

2007-06-14 11:16:27 · answer #9 · answered by nabnel 2 · 1 1

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