How would I solve this?

Question

6.0 *10^3)(2.0 *10 -^10)

Oh my gosh, no wonder i could not get the answer, I was doing it wrong. :/ thank you all for your answers.

Answer 1

First, this is all multiplication, so you don't even really need the parentheses.

6*10^3*2*10^(-10)
With exponents: in case of doubt, write it out.
6*10*10*10*2*(1/10)*(1/10)... with ten (1/10)'s.
Multiply 6 and 2 to get 12.
Cancel out the three 10's with three (1/10)'s
You get 12*(1/10)^7
or if you prefer,
12*10^(-7)
or if you prefer,
1.2*(10^-6)
which is the answer in scientific notation, and most likely the answer your teacher is looking for.

Hope that helps!

Answer 2

The easy way is when multiplying together numbers in scientific notation (with the *10^x), you can add the powers together and multiply the bases together to get your answer:

so you have 2*6 = 12 and 3 - 10 = -7. The end result is 12*10^-7. Usually you want to readjust the base so that it is less than 10. To do this you would divide the 12 by 10 = 1.2 and add one to the power -7 + 1 = -6.

The final answer woul dbe 1.2 * 10^-6

Answer 3

Multiply the 6.0 and the 2.0 to make 12.0
Multiply 10^3 and 10^-10 following normal index rules to make 10^-7
Answer = 12.0 x 10^-7
Put in standard form: 1.2 x 10^-6

Answer 4

(6.0 *10^3)(2.0 *10 -^10)

Remember to add exponents

12 *10^-7 or 1.2*10^-6
.

Answer 5

Just take 6*2*( 10^ (3 - 10) )

(assuming you meant 10^-10 in the second part)

This gives:

12*(10^-7)

When you multiply the same numbers with different exponents, you can add the exponents.

Ex.

(A^5)*(A^3.75) = A^8.75

Answer 6

first solve 10^3=1000 and 10^-10=.0000000001
now your equation is (6*1000)(2*.0000000001) so solve inside each paranthese to get (60000)(.0000000002) and then just multiply the terms to get .0000012