a movie theater sells senior and child tickets for $3 and other tickets for $6.50. One day ,the theater sold?

Question

445 tickets. I t made 2,518 . How many of each kind of ticket did it sell

Answer 1

x = number of $3 tickets
y = number of $6.50 tickets

x + y = 445

x = 445 - y

3x + 6.5y = 2518

3(445 - y) + 6.5y = 2518

1335 - 3y + 6.5y = 2518

1335 +3.5y = 2518

3.5y = 2518 - 1335

3.5y = 1183

y = 338

x = 445 - y

x = 445 - 338

x = 107

there were 107 tickets for $3.00 and 338 tickets for $6.50

Answer 2

Start with all 445 tickets were for at least $3. 445 X $3 = $1335. $2518 - $1335 or $1183 came from the extra money on the $6.50 tickets. Divide the $1183 by $3.50 (the difference between tickets) and get 338.
338 X $6.50 = $2197
107 X $3.00 = $321

Answer 3

you can find out how many of each priced tickets (senior and kids together)....
you need to equations because 2 variables
x + y = 445 change to x = 445-y to isolate a variable and
3x + 6.5y = 2518

plug in
3(445-y) + 6.5y = 2518
multiply through
1335-3y+6.5y = 2518
seperate
3.5y = 1183
divide
y = 338
therefore there were 338 reg adult tickets sold and 107 children or senior tickets sold

Answer 4

Let the no. of senior and child tickets be x
and other tickets be y

so 3x + 6.5y = 2518 //because its the total profit
and x + y =445 // because total no. of tickets sold is 445

solving this answer comes out to be
y = 338 and x= 107

i hop u solve this on ur own

Answer 5

It's a system of equations.

x = childs tickets
y = other tickets

x + y = the number of tickets sold (445)

3x + 6.5y = the amount of money made (2518)

So now we have:

x + y = 445
3x + 6.5y = 2518

Now you have to solve for x in one of the equations. Choose the second one.

Subtract 6.5y from both sides of the equation to get x on its own side.

3x + 6.5y - 6.5y = 2518 - 6.5y

That equals 3x = 2518 - 6.5y because the 6.5ys on the other side of the equation cancel each other out.

Now you have to divide both sides by three.

3x/3 = 2518/3 - 6.5y/3

You wind up with x = 839.3 - 2.17y

Now you have x all by itself. Since x = 839.3 - 2.17y, you can replace x in the other equation that you had, x + y = 445, with 839.3 - 2.17y

Now you have 839.3 - 2.17y + y = 445

Then you just solve.

839.3 - 1.17y = 445

-1.17y = -394.3

Divide both sides by -1.17 to get y alone.

y = 337

That means that the number of adult tickets sold was 337. Now, put that back into the first equation and solve, then put it into the second equation and solve.

445 - 337 = 108.

There were 337 adult tickets sold and 108 children/senior tickets sold.

Answer 6

338 tickets that cost $6.50
And 107 Tickets that cost $3.

In order to solve this you write two equations:

X+Y=445 (The total tickets sold)
2518= 3X+6.5Y

X= Tickets that cost $3
Y= Tickets that cost $6.50

So you take X+Y=445 and make it 445-X=Y.. then substitute Y into the 2nd equation.

2518=3X+6.5(445-X)
Which becomes..

2518=3X+2892.5-6.5X
-374.5= -3.5X
And when you divide each by -3.5.. X=107

Plug 107 as X back into the ORIGINAL equation of X+Y=445
so its.. 107+Y=445

Therefore it is 338=Y

Hope that helps!

Answer 7

A + C = 548 C = 548 - A 6.5A + 3.5C = 2881 6.5A + 3.5(548 - A) = 2881 6.5A + 1918 - 3.5A = 2881 3A = 963 A = 321 C = 227