Some AlF3 is soluble, but if you make a supersaturated solution, then some will precipitate out, but it may take some time for the precipitation reaction to occur (like overnight).
You can make a supersauturated solution by etching aluminum or aluminum alloys in a HF/nitric acid bath. (but if you are actually working with HF solutions - be REAL careful with the HF acid!! Read up on it first - it's BAD stuff!!!) The aluminum fluoride (hydrated) shows up as a white crust on the tank bottom and sides in a commercial aluminum etching operation.
The question is how much remains in solution, so for that you need a solubility product. That sort of data is most easily found in the older literature, because that type of inorganic chemistry isn't so popular anymore. I looked it up once in an old, yellowed book on solubility, but don't have that info anymore.
2007-06-14 07:04:39
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answer #1
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answered by WildOtter 5
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Yes, it should be because it doesn't defy the rules of unsoluble substances. Alkali salts and ammonia are always soluble.
2007-06-14 13:37:50
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answer #2
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answered by Anonymous
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actually you are not clear in what it is soluble in polar or non polar solvent .
like dissolves like rule follows
those compounds which have dipole dipole interactions are soluble in dipole dipole interactions
compounds having
nh fh and oh bonds are soluble in water as there is hydrogen bonding both in water and the compound
alf is soluble in water as they both have dipole dipole forces of attraction
2007-06-14 13:45:25
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answer #3
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answered by neha 2
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AlF3 is soluble, as are pretty much all fluorides.
Fluorides are the most soluble of all halides.
2007-06-14 13:38:17
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answer #4
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answered by Gervald F 7
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