factor....?

Question

5x^2 + 10x - 4

Answer 1

Use the Quadratic Formula which, is...
x = [-b +/- V`b^2 - 4ac] / 2a

First: 3 terms...a = 5; b = 10; c = -4
Sec: substitute the terms with the corresponding variables.

x = [-10 +/- V`10^2 - 4(5)(-4)] / 2(5)

x = [-10 +/- V`10*10 - 4(5)(-4)] / 10

x = [-10 +/- V`100 - 4(5)(-4)] / 10

x = [-10 +/- V`100 - 20(-4)] / 10

x = [-10 +/- V`100 - (-80)] / 10

x = [-10 +/- V`100 + 80] / 10

x = [-10 +/- V`180] / 10

x = [-10 +/- V`2*2*3*3*5] / 10

x = [-10 +/- 2(3)V`5] / 10

x = [-10 +/- 6V`5] / 10

Third: there are 2 solutions.

a. x = [-10 + 6V`5] / 10
x = -10/10 + (6/10)V`5
x = -1 + (3/5)V`5

b. x = [-10 - 6V`5] / 10
x = -10/10 + (6/10)V`5
x = -1 + (3/5)V`5

Answer 2

The solutions (from the quadratic equation) are
[-10 +/- sqrt(100-4*5*-4)]/(2*5)
[-10 +/- sqrt(180)]/10

since 180 is not a perfect square, the answer is not rational and thus it cannot be factored over the integers.
Sorry!

Answer 3

5x^2 + 10x - 4
x = [-10 +/- sqrt(10^2-4(5)(-4)]/(2*5)
x = [-10 +/- sqrt(180)]/10
x= [-10 +/- 6sqrt(5)]/10
x = -1 +.6sqrt(5) and x = -1 -.6sqt(5)
Thus the factors are:
(x+1-.6sqrt(5))(x+1+.6sqrt(5))

Answer 4

The expression can not be factored.

Answer 5

Factorisation not possible.

Answer 6

-4 i'm 100% sure