This is math...
The points (3,4), (11,6), (23,9) all lie on a line... the question is calculate the coordinates of another point on this same line whose x coordinate is greater than 800.. ? I'm confused.. i used all the ways but it didn't work... please explain if you know the way .....to know the answer
2007-06-14
05:37:04
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7 answers
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asked by
hey
3
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Science & Mathematics
➔ Mathematics
hey you have to be patient
a straight line equation = mx+b where m=gradient b= intercept
as 3,4 is a point and 11,6
then find the gradient which is
y2-y1/x2-x1
in this case y1=4 x1=3
and y2=6 and x2=11
so 6-4/11-3
2/8=1/4
so m=1/4
and using this equation(maybe it is new but really useful) to find the equation of the straight line
y-y1=m(x-x1) so let's take (3,4)
y-4=1/4(x-4)
multiplie the equation by 4 to get rid of the quarter
4y-16=x-4
rearrange
4y=x+12
so as more than 800 as the question asks you follow these steps:
1-let's find when x=800
4y=800+12
4y=812
divide by 4
812/4=203
2-if when x=800,y=203
so the more is the x the more is the y
so y>203 when x >800
and that is the answer
so if you want 803 back to the equation
and don't forget crediting the best answer!!!!please
2007-06-14 05:55:34
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answer #1
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answered by casim 2
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If all the points lie on a line, the slope will be the same for any pair of points. The slope is defined as the change in y divided by the change in x, so:
slope = (4-6)/(3-11) = (-2)/(-8) = 1/4
slope = (4-9)/(3-23) = (-5)/(-20) = 1/4
slope = (6-9)/(11-23) = (-3)/(-12) = 1/4
All three points have the same slope. The next thing to check is the intercept. Thus far it has been established that Y = 0.25X + B, abd "B" is the intercept.
4 = 3/4 + B, B=3.25
6 = 11/4 + B, B=3.25
9 = 23/4 + B, B=3.25
This is proof all three points lie on a line described by the formula Y = 0.25X + 3.25
If x=801, then Y = 203.5
2007-06-14 12:57:40
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answer #2
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answered by Roger S 7
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A line is defined by two points. Let (3,4) be point A, and (11,6) be point B. The equation of line AB is:
(x-xA) / (xB-xA) = (y-yA) / (yB-yA)
where xA=3; yA=4; xB=11; yB=6;
So the equation is:
(x-3)/(11-3) = (y-4)/(6-4)
(x-3)/8 = (y-4)/2
x-3=4(y-4)
x-3=4y-16
The final form of the equation is: x-4y+13=0
By substituting the coordinates of the third point given, we check if our equation is correct: 23-4*9+13 = 23-36+13= 0. So it is ok.
If the x coordinate has to be greater than 800, you just take any number greater than 800 and substitute it in the equation:
for example let our point be M. So xM should be greater than 800. Let xM be 815. Then 815 - 4y+13=0. So 4y= 828, y=207.
M(815,217)
You can take any point you like and just substitute in the equation. Just be careful that xM should be greater than 800.
2007-06-14 12:55:40
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answer #3
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answered by Anonymous
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First, find the equation of the line.
(4-6)/(3-11) = -2/-8 = 1/4
y = (1/4)x + b substitute given points
4 = (1/4)3 + b => 4 = 3/4 + b => b = 13/4 So
y = (1/4)x + 13/4 Check
6 = (1/4)*11 + 13/4 = 11/4 + 13/4 = 24/4 Check âº
Then
y = (1/4)*1000 + 13/4 = 250 + 13/4 = 1013/4
I used 1000 for x because it was easy to work with, but you can use anything you like âº
Doug
2007-06-14 12:46:57
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answer #4
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answered by doug_donaghue 7
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take the slope of the line
rise over run
m= y2-y1/x2-x1
y=mx+b
when you draw the line you will have b (y-intercept)
when you calculate the slope, you will have m
plug in a number greater than 800 and you will get a set of coordinates
2007-06-14 12:43:33
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answer #5
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answered by oatmeal cookies 2
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use slope (y2-y1)/(x2-x1)
the slope between each pair of points is 1/4; same as rise over run
1 = y2-4
-- --------
4 803-3 (i chose 803 so that you get 800 when you subtract and that's divisible by 4)
cross multiply and you'll get 200=y2-4, so add 4 and y2=204
(803, 204)
2007-06-14 12:46:16
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answer #6
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answered by hrhbg 3
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(803,204)
2007-06-14 12:45:14
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answer #7
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answered by nikkoj1975 4
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