Some other physics problems?

Question

1) A 15.16ohm coffee maker & a 16.50ohm frying pan are connected in series across a 120V source of voltage. A 22.21ohm bread maker is also connected across the 120V source & is in parallel w/the series combination. Find the total current supplied by the source of voltage.

2) A 64.0ohm resistor is connected in parallel w/a 112ohm resistor. This parallel group is connected in series with a 18.0ohm resistor. The total combination is connected across a 12V battery. (a) find the current and (b) the power dissipated in the 112ohm resistor.

3) A new "D" battery has an emf of 1.50V. When a wire of negligible resistance is connected between the terminals of the battery, a current of 27.8A is produced. Calculate the internal resistance of the battery.

4) Three capacitors (4.13, 6.01, & 12.5microF) are connected in series across a 57.0V battery. Calculate the voltage across the 4.13microF capacitor.

Answer 1

1) This is a circuit with 15.16+16.5 ohm in parallel with 22.1 ohm all in parallel with 120V.
Reduce the resistors to find the equivalent and divide the voltage by that amount:

1/Req=1/(15.16+16.5)+1/22.1

2. Similar
the parallel reduces as
R1=64+112/(64*112)
total resistance is 18+R1
current is V/R
To compute the current in the 112 ohm resistor, first compute the voltage across the resistor:
(V/R)*R1 is the voltage
and voltage/112 is the current. Power is V*I

3. Using Ohm's Law:
V=I*R
V is 1.5 and I is 27.8, so
R+1.5/27.8

4. The total capacitance is the sum of the three.
The voltage on each is 57*c/ctotal

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Answer 2

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