the options are:
A: double
B: half
C: 8 times
D: 1/8 times
2007-06-14 03:33:57 · 5 answers · asked by Swathi M 1 in Science & Mathematics ➔ Physics
the dimensions (ie units) of G are
Length^3/(mass)(time)^2
write [G] = [ L^3/m*t^2 ]
let G' be the new G after you replace L by 2L, then
[ G' ]
= [ (2L)^3/m*t^2 ]
=[2^3 *L^3/m*t^2 ]
=8[ L^3/m*t^2 ]
=8[G]
so G will become 8 times larger
the answer is C
2007-06-14 03:52:29 · answer #1 · answered by The Wolf 6 · 0⤊ 0⤋
the constant is just that, constant. it never changes, but the force of gravity will decrease by an inverse square, or 1/2^2= 1/4
2007-06-14 10:37:04 · answer #2 · answered by terrell f 2 · 0⤊ 0⤋
Nothing.
The "value of universal gravitation constant G" is just that -- CONSTANT.
.
2007-06-14 10:42:26 · answer #3 · answered by Anonymous · 0⤊ 0⤋
we know F=GMm/r^2
so G=Fr^2/Mm
now according to this G shud be 4 times.
2007-06-14 10:40:52 · answer #4 · answered by Rachit Goel 1 · 0⤊ 1⤋
???
Huh??? The unit length of --what--?
Doug
2007-06-14 10:38:27 · answer #5 · answered by doug_donaghue 7 · 0⤊ 0⤋