How can i calculate this with a formula?

(n)*(n-1)*(n-2)*(n-3)...*(n-x)/(y)*(y-1)...*(y-x)

2007-06-14 03:14:22 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics

example:
(8/17)*(7/16)*(6/15).

2007-06-14 03:18:18 · update #1

n * (n-1) * (n-2) * ... * (n - x) = n!/(n - x - 1)!

2007-06-14 03:21:17 · answer #1 · answered by Mathsorcerer 7 · 0⤊ 0⤋

follow product of an AP

2007-06-14 03:21:49 · answer #2 · answered by ? 4 · 0⤊ 0⤋

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