determine the distance that a baseball travels if it is thrown with a velocity of 110 ft/sec at an angle of 28

Question

determine the distance that a baseball travels if it is thrown with a velocity of 110 ft/sec at an angle of 28 degrees relative to the level ground

Answer 1

x= 110 cos(28) *t
y=- 1/2(32.15)t^2+110sin(28) t
y= 0 for t=0 and for t =110sin(28) /16.08=3.21s
so x= 312 feet rounded to the nearest integer

Answer 2

It's probably easiest if you use 32 f/s² for gravitational acceleration (g).
Fcirst, break up the velocity into its vertical and horizontal components. Ues the vertical component (Vy) to find the time the ball is in the air
Vy*t - gt²/2 = 0 Then multiply the time you just found by the horizontal component of the original velocity vector to get the horizontal distance.

No, I'm --not-- going to do your homework for you.

Doug

Answer 3

the distance travelled by the base ball can be calcuated as follows.
Assuming that the baseball took - off from the ground
Time of flight is = 2 * u * sin (28) / 32.18
= 2* 110*sin28/32.18
= 3.2096 sec

distance travelled is = 110cos28*3.2096
= 311.7264 ft