find the equation for the asymptotes of the hyperbola y^2/4 - x^2/16 =1?

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find the equation for the asymptotes of the hyperbola y^2/4 - x^2/16 =1?

2007-06-14 00:28:05 · 2 answers · asked by got_milk_biotch 1 in Science & Mathematics ➔ Mathematics

2 answers

To find the equations of the asymptotes, you change the 1 on the RHS to 0. That gives:
y^2 / 4 - x^2 / 16 = 0
y^2 / 4 = x^2 / 16
Taking the square root:
y / 2 = +/- x / 4
y = +/- x/2.

2007-06-14 00:45:05 · answer #1 · answered by Anonymous · 0⤊ 0⤋

y/2-x/4=0 and y/2+x/4=0

2y-x=0 and 2y+x=0

2007-06-14 09:09:07 · answer #2 · answered by santmann2002 7 · 0⤊ 0⤋