Write an equation in point-slope form of a line that has a slope of 1.5 and passes through the point (16,-5)
2007-06-12 22:28:30 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Y - Y0 = m( X - X0 )
m = 1.5
Y0 = -5
X0 = 16
that's all !
2007-06-13 00:47:13 · answer #1 · answered by ՎԱՀԷ 4 · 1⤊ 0⤋
m = 1.5 = 3/2
(16,-5)
y = mx + c
-5 = (3/2)(16) + c
c = -5 - 24
c = -29#
y = (3/2)x - 29
2y = 3x - 58#
2007-06-12 22:57:36 · answer #2 · answered by jackleynpoll 3 · 0⤊ 0⤋
y = mx + c
m=1.5 and (16,-5) is on the line
So, -5 = 1.5 (16) + c
So, -5 = 24 + c
So, c=-29
Equation is y = 1.5 x - 29
2007-06-12 22:36:18 · answer #3 · answered by Anonymous · 0⤊ 0⤋
y + 5 = 1.5.(x - 16)
y + 5 = 1.5 x - 24
y = 1.5 x - 29
2007-06-12 23:10:05 · answer #4 · answered by Como 7 · 0⤊ 0⤋
y-y1=m(x-x1)
m=1.5
(x1,y1)=(16,-5)
so the equation is
y-(-5)=1.5(x-16)
y+5=1.5x-24
1.5x-y-29=0
or, 3x-2y-58=0 ........on multiplying the whole equation by 2.
2007-06-12 22:57:07 · answer #5 · answered by Jain 4 · 0⤊ 0⤋
y = 1.5 x - 29
2007-06-12 22:34:08 · answer #6 · answered by s_jmp 2 · 0⤊ 0⤋