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where does the equation (E-Ir=IR) comes from where E=EMF ,I=current, R=external resistor and r= internal ressistance.

2007-06-12 22:19:42 · 3 answers · asked by madxplrr 1 in Science & Mathematics Physics

3 answers

http://farside.ph.utexas.edu/teaching/302l/lectures/node43.html

2007-06-12 22:25:25 · answer #1 · answered by Anonymous · 0 0

The voltage source equivalent model (Thevenin Equivalent) of a battery consists of a perfect voltage source E in series with a resistor r (called the Thevenin equivalent source resistance). When current is flowing from the - to + node, there is a voltage drop across the internal resistance which is Ir so that the effective terminal voltage becomes E - Ir. This is the terminal voltage and the rest is simply Ohms Law.

Doug

2007-06-12 22:36:28 · answer #2 · answered by doug_donaghue 7 · 0 0

You have not mentioned the terminal voltage in your question.

Actually E- Ir = V, the terminal voltage

It comes from Ohm's law, which we take on faith.

r is the internal resistance, which accounts for the voltage drop Ir when a current I is supplied.

So the actual voltage from the battery we get is V= E- Ir the terminal voltage, which decreases as the I decreases.

2007-06-12 23:31:38 · answer #3 · answered by Karoly 2 · 0 0

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