it must be 42+43 = 85
You can get it just by trying numbers in your head (that's what I did), but I guess the best way would be to divide 85 in half, which gives you 42.5, so you know it must be the closest two numbers on either side of that!
2007-06-12 21:41:57
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answer #1
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answered by Anonymous
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let:
x 1st integer
x+1 2nd integer
solution:
x + (x+1) = 85
2x +1 =85
2x = 85 - 1
x = 84/2
x = 42
the 2nd integer is
(x+1) = 42 + 1 = 43
therefore the two consecutive integers are 42 & 43.
2007-06-13 00:30:55
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answer #2
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answered by norie 2
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Two consecutive integers can be represented by the terms x and x+1.
For your problem x + x+1 = 85 or 2x + 1 = 85.
From that, 2x = 84 and x = 42.
x+1 will therefore be 43 and there you have it.
2007-06-12 21:46:07
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answer #3
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answered by John B 4
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Two consecutive integers: let n be the first, m the second. Because they are consecutive, we know that m = n + 1. Add them together and what do you get? n + n + 1. How else can we state that? 2n + 1
2n+1 = 85
subtract 1 from both sides
2n = 84
n = 42
m = n +1
m = 42 + 1
m = 43
2007-06-12 21:52:08
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answer #4
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answered by Pete 2
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Let the integrs be x and x+1
Therefore,
x+x+1=85
or,2x+1=85
or.2x=85-1=84
or,x=84/2=42
Therefore the integers are 42 and 43.
2007-06-12 21:50:21
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answer #5
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answered by alpha 7
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the two are 42 and 43
2007-06-12 22:04:08
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answer #6
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answered by Brocko222 4
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integers = numbers without decimals.
The answer is 42 and 43.
Hope this helps!
2007-06-12 21:43:31
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answer #7
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answered by p37ry 5
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42 and 43.
2007-06-12 21:42:32
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answer #8
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answered by pullmyfinger 1
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x + (x + 1) = 85
2x + 1 = 85
2x = 84
x = 42
Numbers are 42 and 43.
2007-06-12 21:50:23
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answer #9
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answered by Como 7
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bhai... too silly.
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This is the best answer.. :)
2007-06-12 22:00:21
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answer #10
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answered by vinayaniv 2
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