82. 2 times a number, increased by 28, is less than or equal to 6 times that number.
Match each inequality on the right with a statement on the left.
2007-06-12 18:07:15 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
let "a number" be x
2 * x (2 times a number)...
(2 * x) + 28 (increased by 28)...
(2 * x) + 28 <= (is less than or equal to)...
[(2 * x) + 28] <= [6 * x] (6 times that number)
[(2 * x) + 28] <= [6 * x]
2007-06-12 18:11:23 · answer #1 · answered by whitesox09 7 · 0⤊ 0⤋
Kyle is correct, but you can take it a step further.
After translating the problem into an equation...
2x + 28 <= 6x ... you can solve this with Algerbra.
First, Subtract 2x from both sides of the equation which yields...
28 <= 4x
Divide both sides of the equation now by 4 to solve for x.
7 <= x
2007-06-12 18:19:38 · answer #2 · answered by tehmpus 2 · 0⤊ 0⤋
2x+28<=6x
or 28<=4x
or 7<=x
2007-06-12 18:37:48 · answer #3 · answered by Sumita T 3 · 0⤊ 0⤋
"2 times a number" ............ 2x
"increased by 28" .............. 2x + 28
"is less than or equal to" .... 2x + 28 ≤
"6"
2x + 28 ≤ 6
most of this is just word for word translation.
2007-06-12 18:12:26 · answer #4 · answered by Philo 7 · 0⤊ 0⤋
the main factor is to grant (algebraic) names to the values in touch. Then translate the text cloth step-by utilizing-step! you have 3 a while in the 1st occasion. permit's call them L, S and J - in basic terms chosen because of fact the 1st letters from the three names with a view to make the letters actually recognised. then you extremely pass step-by utilizing-step: Leah is 6 years older than sue: L=S+6. John is 5 years older than Leah: J=L+5 the full is 40-one: L+S+J=40-one the subsequent step is greater technical. eliminate variables by utilizing fixing one equation for one variable and substitute the answer (algebraic as could be) into the others: L=S+6 we see L is already by myself on the left hand area so substitute it into the different equations J=L+5 we substitute L for S+6 and get J=(S+6)+5=S+11 L+S+J=40-one we substitute L for S+6 and acquire (S+6)+S+J=2S+J+6=40-one Now J=S+11 and for this reason 2S+J+6=2S+(S+11)+6=40-one We see that 3S=24 or S=8. understanding that we are able to calculate the different a while.
2016-10-09 02:36:45 · answer #5 · answered by ? 4 · 0⤊ 0⤋