2/v+2 - 1/v-3=0
2007-06-12 17:45:55 · 5 answers · asked by mecca laran 4 in Science & Mathematics ➔ Mathematics
2/(v+2) - 1/(v-3)=0
[2(v-3)-(v+2)]/(v+2)(v-3) = 0
2v - 6 - v - 2 = 0
v - 8 = 0
v = 8#
2007-06-12 17:51:06 · answer #1 · answered by jackleynpoll 3 · 0⤊ 0⤋
[2(v-3)-1(v+2)]/[(v+2)(v-3)] = 0
2v-6-v-2 = 0
v-8 = 0
v = 8
2007-06-13 00:54:07 · answer #2 · answered by AL 2 · 0⤊ 0⤋
IT = 4
2007-06-13 00:48:42 · answer #3 · answered by janay beamer 2 · 0⤊ 1⤋
First you would consolidate the info by combining like terms 1/v -1 = 0
Then you do reverse PEMDAS, Subtraction First 1/v = -1
Then Divide, v = -1/1
There's your answer. V= -1
2007-06-13 00:50:06 · answer #4 · answered by DmnSlyr6 2 · 0⤊ 1⤋
lcd is v+2 v-3
2(v-3)-1(v+2)=0
2v-6-v-2=0
v-8=0
v=8
answer is 8/v^2-v-6
2007-06-13 00:52:13 · answer #5 · answered by Dave aka Spider Monkey 7 · 0⤊ 1⤋