algebra 1 question!?

Question

solve by cross multiplying

x-3/x-9=x-8/x-1

Answer 1

hi brittany...

well, cross multiplying is basically a short cut to getting rid of fractions in an equation.. if you had a simpler question like
a/b = c/d

to get rid of the fractions using cross multiplication you would multiply the numerator on the left side with the denominatior or the right side and the number on the right side with the denominator on the left side which would look like

a * d = c * b

so applying it to your problem you

x-3/x -9 = x-8/x-1 would become (x-3)(x-1) = (x-9)(x-8)

now it's expand both sides, collect like terms and solve for x

x^2 -4x + 3 = x^2 -17x + 72
13x = 69

x = 69/13

Hope this helps...

Cheers,
Mark

Answer 2

x^2 - 4x +3 = x^2-17x+72
13x = 69
x = 69/13

Answer 3

(x-3)/(x-9)=(x-8)/(x-1)
(x-3)(x-1) = (x-8)(x-9)
x^2 - 4x + 3 = x^2 -17x + 72
17x - 4x = 72 - 3
13x = 69
x = 69/13
x = 3#

Answer 4

(x-3)(x-1)=(x-9)(x-8)

x^2-1x-3x+3=x^2-8x-9x+72

x^2-4x+3=x^2-17x+72

-69=21x

x=-3.2857